Ada jejak: 2009

Minggu, 15 November 2009

Minggu, 08 November 2009

latihan logika& alogoritma

Soal No 1.

#include

main()

{

char a;

a=1;

clrscr;

{

printf("1 2 3 4 5 \n");

printf("1 2 3 4 \n");

printf("1 2 3 \n");

printf("1 2\n");

printf("1\n");

a++;

}

while(a<=5);

getch();

}

Output:

1 2 3 4 5

1 2 3 4

1 2 3

1 2

Soal No 2.

#include

main()

{

char a;

a=1;

clrscr;

{

printf("1 2 3 4 5 \n");

printf("6 7 8 9 10 \n");

printf("11 12 13 14 15 \n");

a++;

}

while(a<=5);

getch();

}

Output:

1 2 3 4 5

6 7 8 9 10

11 12 13 14 15

Soal No 3.

#include

main()

{

char a;

a=1;

clrscr;

{

printf("1 2 3 4 5 \n");

printf("6 7 8 9 \n");

printf("10 11 12 \n");

printf("13 14\n");

printf("15\n");

a++;

}

while(a<=5);

getch();

}

Output:

1 2 3 4 5

6 7 8 9

10 11 12

13 14

Soal No 4.

#include

#include
main()

{

char a;

a=1;

clrscr;

{

printf("2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110\n");

printf("Bilangan Genap\n");

a++;

}

while(a<=5);

getch();

}

Output :

2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110

Bilangan Genap

Soal No 5.

#include

main()

{

char a;

a=1;

clrscr;

{

printf("1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 = 100\n");

printf("Bilangan Ganjil\n");

a++;

}

getch();

}

Output:

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 = 100

Bilangan Ganjil

Soal No 6.

#include

main()

{

char a;

a=1;

clrscr;

{

printf("1 =1\n");

printf("1 + 2 =3\n");

printf("1 + 2 + 3 =6\n");

printf("1 + 2 + 3 + 4 =10\n");

printf("1 + 2 + 3 + 4 + 5 =15\n");

printf("ANDA TIDAK BOLEH MENERUSKANNYA KARENA BISA MENNYEBABKAN PROGRAM TIDAK DITERIMA");

printf("\n");

printf("Gw liat yg bener kya gmana dunk");

printf("\n");

printf("Dari contoh 1-6 Bukan Program yg dianjurkan oleh Dosen");

a++;

}

getch();

}

Output :

1 =1\n");

1 + 2 =3\n");

1 + 2 + 3 =6\n");

1 + 2 + 3 + 4 =10\n");

1 + 2 + 3 + 4 + 5 =15\n");

ANDA TIDAK BOLEH MENERUSKANNYA KARENA BISA MENNYEBABKAN PROGRAM TIDAK DITERIMA

Gw liat yg bener kya gmana dunk

Dari contoh 1-6 Bukan Program yg dianjurkan oleh Dosen

Selasa, 03 November 2009

Penulisan LOOPING

Contoh penulisan proses LOOP

Statement While
Statement Do…….While
Statement FOR

Statement FOR Positif
Statement FOR Negatif
Statement FOR berasarang (Nested Loop)

1. Statement While

int bil=1;

while(bil<=5)

cout<

++bil; bil = bil + 1

Output: 12345

Jwb :

Bil = 1	Bil<=5	Cetak bil	Bil= bil + 1
1	1<=5	1	2
2	2<=5	2	3
3	3<=5	3	4
4	4<=5	4	5
5	5<=5	5	6
6	6<=5

2. Statement Do….While

int bil=2;

cout<

bil+=2;

while (bil>=10);

output: 2 4 6 8 10

jwb:

Bil=2	Cetak bil	Bil + 2	Bil>=10	Y/T
2	2	4	4>=10	T
4	4	6	6>=10	T
6	6	8	8>=10	T
8	8	10	10>=10	T
10	10	12	12>=10	Y

3. Statement FOR

Contoh 1.a

#include

Void main()

{

Int I,N;

N = 45;

I = 1;

While (I<=5);

{

Printf (“\n%i,”N);

N = N + 5

I = I + 1

}

Output: 45 50 55 60 65

Jwb:

N = 45	I = 1	I<=5	Y/T	Cetak N	N = N + 5	I = I + 1
45	1	1<=5	Y	45	50	2
50	2	2<=5	Y	50	55	3
55	3	3<=5	Y	55	60	4
60	4	4<=5	Y	60	65	5
65	5	5<=5	Y	65	70	6
70	6	6<=5	T

Contoh 1.b

#include

Void main()

{

Int I,N;

N = 45;

I = 1;

While (I<=5);

{

N = N + 5

I = I + 1

}

Printf (“\n%i,”N);

}

Output: 70

Jwb :

N = 45	I = 1	I<=5	Y/T	N = N + 5	I = I + 1	Cetak N
45	1	1<=5	Y	50	2
50	2	2<=5	Y	55	3
55	3	3<=5	Y	60	4
60	4	4<=5	Y	65	5
65	5	5<=5	Y	70	6
70	6	6<=5	T			70

Contoh 1.c

#include

Void main()

{

Int I,N;

N = 45;

I = 1;

While (I<=5);

{

N = N + 5

Printf (“\n%i,”N);

I = I + 1

}

Output: 45 50 55 60 65

Jwb:

N = 45	I = 1	I<=5	Y/T	N = N + 5	Cetak N	I = I + 1
45	1	1<=5	Y	50	45	2
50	2	2<=5	Y	55	50	3
55	3	3<=5	Y	60	55	4
60	4	4<=5	Y	65	60	5
65	5	5<=5	Y	70	65	6
70	6	6<=5	T

Contoh 2

#include

Void main()

{

Int I,N;

N = 10;

I = 10;

While (N<=100);

{

N = N + I

Printf (“\n%i,”N);

I = I + 5;

}

Output: 20 35 55 80 110

Jwb:

N = 10	I = 1	N<=100	Y/T	N = N + 1	Cetak N	I = I + 5
10	10	10<=100	Y	20	20	15
20	15	15<=100	Y	35	35	20
35	20	20<=100	Y	55	55	25
55	25	25<=100	Y	80	80	30
80	30	30<=100	Y	110	110	35
110	35	35<=100	T

Contoh 3.a

#include

Void main()

{

Int I,N;

N = 10;

X = 10;

T = 0;

While (T<=100);

{

T = T + N;

N = N + X;

X = X + 5;

}

Printf (“\n%i,”T);

}

Output: 120

Jwb:

N=10	X=10	T=0	T<=100	Y/T	T =T+N	N =N+X	X=X+5	Cetak T
10	10	0	0<=100	Y	10	20	15
20	15	10	10<=100	Y	30	35	20
35	20	30	30<=100	Y	65	55	25
55	25	65	65<=100	Y	120	80	30
80	30	120	120<=100	T				120

Contoh 3.b

#include

Void main()

{

Int I,N;

N = 10;

X = 10;

T = 0;

While (T<=100);

{

T = T + N;

Printf (“\n%i,”T);

N = N + X;

X = X + 5;

}

Output: 10 30 65 120

Jwb:

N=10	X=10	T=0	T<=100	Y/T	T =T+N	Cetak T	N =N+X	X=X+5
10	10	0	0<=100	Y	10	10	20	15
20	15	10	10<=100	Y	30	30	35	20
35	20	30	30<=100	Y	65	65	55	25
55	25	65	65<=100	Y	120	120	80	30
80	30	120	120<=100	T

Nested FOR

Contoh 1.a

int I.J;

for (I = 1, 1<=3;I++);

{

for(J=1;J<=5;J++);

{

Printf(“\n%i”,I);

}

Output: 1 1 1 1 1

2 2 2 2 2

3 3 3 3 3

Jwb:

I=1	I<=3	Y\T	J=1	J<=5	Y\T	Cetak I	J++	I++
1	1<=3	Y	1	1<=5	Y	1	2
			2	2<=5	Y	1	3
			3	3<=5	Y	1	4
			4	4<=5	Y	1	5
			5	5<=5	Y	1	6
			6	6<=5	T			2
2	2<=3	Y	1	1<=5	Y	2	2
			2	2<=5	Y	2	3
			3	3<=5	Y	2	4
			4	4<=5	Y	2	5
			5	5<=5	Y	2	6
			6	6<=5	T			3
3	3<=3	Y	1	1<=5	Y	3	2
			2	2<=5	Y	3	3
			3	3<=5	Y	3	4
			4	4<=5	Y	3	5
			5	5<=5	Y	3	6
			6	6<=5	T			4
4	4<=3	T

Contoh 1.b

int I.J;

for (I = 1, 1<=3;I++);

{

for(J=1;J<=5;J++);

{

Printf(“\n%i”,J);

}

Output: 1 1 1

2 2 2

3 3 3

4 4 4

5 5 5

Jwb:

I=1	I<=3	Y\T	J=1	J<=5		Y\T	Cetak J	I++		J++
1	1<=3	Y	1	1<=5		Y	1	2
2	2<=3	Y					1	3
3	3<=3	Y					1	4
4	4<=3	T								2
1	1<=3	Y	2	2<=5		Y	2	2
2	2<=3	Y					2	3
3	3<=3	Y					2	4
4	4<=3	T								3
1	1<=3	Y	3	3<=5		Y	3	2
2	2<=3	Y					3	3
3	3<=3	Y					3	4
4	4<=3	T								4
1	1<=3	Y	4	4<=5		Y	4	2
2	2<=3	Y					4	3
3	3<=3	Y					4	4
4	4<=3	T								5
1	1<=3	Y	5	5<=5		Y	5	2
2	2<=3	Y					5	3
3	3<=3	Y					5	4
4	4<=3	T							6
			6		6<=5	T

Minggu, 15 November 2009

Minggu, 08 November 2009

latihan logika& alogoritma

Selasa, 03 November 2009

Penulisan LOOPING

jang lupa kasih makan hamster ku dLu iia